What are the solutions to the equation x^3+6x^2-2x-12=0 ?

The solutions to the equation x^3+6x^2-2x-12=0 are x=-6,x=-sqrt(2),x=sqrt(2)

Find the zeros of x^3+6x^2-2x-12=0

The zeros of x^3+6x^2-2x-12=0 are x=-6,x=-sqrt(2),x=sqrt(2)

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x^{3} + 6 x^{2} - 2 x - 12 = 0

x = - 6, x = - 2, x = 2

Decimal Notation

x = - 6, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

x^{3} + 6 x^{2} - 2 x - 12 = 0

Factor

x^{3} + 6 x^{2} - 2 x - 12 : (x + 6) (x + 2) (x - 2)

(x + 6) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 6, x = - 2, x = 2

x^{4} + 7 x^{3} + 5 x^{2} - 31 x - 30 = 0

- 4000 + 1500 x - 120 x^{2} + x^{3} = 0

x^{3} + 9 x^{2} = 4 x^{2} - x - 5

50 = 4 x (6 - x) (5 - x)

- 6 b^{3} + 7 = - 35

What are the solutions to the equation x^3+6x^2-2x-12=0 ?
The solutions to the equation x^3+6x^2-2x-12=0 are x=-6,x=-sqrt(2),x=sqrt(2)
Find the zeros of x^3+6x^2-2x-12=0
The zeros of x^3+6x^2-2x-12=0 are x=-6,x=-sqrt(2),x=sqrt(2)