What are the solutions to the equation x^3+2x^2=16x+32 ?

The solutions to the equation x^3+2x^2=16x+32 are x=-2,x=-4,x=4

Find the zeros of x^3+2x^2=16x+32

The zeros of x^3+2x^2=16x+32 are x=-2,x=-4,x=4

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x^{3} + 2 x^{2} = 16 x + 32

x = - 2, x = - 4, x = 4

Solution steps

x^{3} + 2 x^{2} = 16 x + 32

Move

32

to the left side

x^{3} + 2 x^{2} - 32 = 16 x

Move

16 x

to the left side

x^{3} + 2 x^{2} - 32 - 16 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} + 2 x^{2} - 16 x - 32 = 0

Factor

x^{3} + 2 x^{2} - 16 x - 32 : (x + 2) (x + 4) (x - 4)

(x + 2) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 4 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 2, x = - 4, x = 4

n^{3} = 256

x^{5} + 32 i = 0

0 = x^{3} + 6 x^{2} - 15 x + 8

x^{4} + 625 = 0

r, r^{3} = \frac{3 v}{4 π}

What are the solutions to the equation x^3+2x^2=16x+32 ?
The solutions to the equation x^3+2x^2=16x+32 are x=-2,x=-4,x=4
Find the zeros of x^3+2x^2=16x+32
The zeros of x^3+2x^2=16x+32 are x=-2,x=-4,x=4