What are the solutions to the equation (x-7)(x+5)(2x-3)=0 ?

The solutions to the equation (x-7)(x+5)(2x-3)=0 are x=7,x=-5,x= 3/2

Find the zeros of (x-7)(x+5)(2x-3)=0

The zeros of (x-7)(x+5)(2x-3)=0 are x=7,x=-5,x= 3/2

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(x - 7) (x + 5) (2 x - 3) = 0

x = 7, x = - 5, x = \frac{3}{2}

Decimal Notation

x = 7, x = - 5, x = 1.5

Solution steps

(x - 7) (x + 5) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or x + 5 = 0 or 2 x - 3 = 0

Solve

x - 7 = 0 : x = 7

Solve

x + 5 = 0 : x = - 5

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 7, x = - 5, x = \frac{3}{2}

15 t^{3} - 15 t^{2} + 20 t = 5 t

x, x^{3} + y^{3} = 16

x^{3} = \frac{27}{125}

(x - 3)^{3} = 8

x^{3} - 12 x^{2} + 36 x = 0

What are the solutions to the equation (x-7)(x+5)(2x-3)=0 ?
The solutions to the equation (x-7)(x+5)(2x-3)=0 are x=7,x=-5,x= 3/2
Find the zeros of (x-7)(x+5)(2x-3)=0
The zeros of (x-7)(x+5)(2x-3)=0 are x=7,x=-5,x= 3/2