What are the solutions to the equation 2x^3+7x^2+2x-3=0 ?

The solutions to the equation 2x^3+7x^2+2x-3=0 are x=-1,x= 1/2 ,x=-3

Find the zeros of 2x^3+7x^2+2x-3=0

The zeros of 2x^3+7x^2+2x-3=0 are x=-1,x= 1/2 ,x=-3

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2 x^{3} + 7 x^{2} + 2 x - 3 = 0

x = - 1, x = \frac{1}{2}, x = - 3

Decimal Notation

x = - 1, x = 0.5, x = - 3

Solution steps

2 x^{3} + 7 x^{2} + 2 x - 3 = 0

Factor

2 x^{3} + 7 x^{2} + 2 x - 3 : (x + 1) (2 x - 1) (x + 3)

(x + 1) (2 x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 1 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 1, x = \frac{1}{2}, x = - 3

t^{4} - 2401 = 0

x^{3} - x - 4 = 0

2000 x + 200 x^{3} - 1000 = 0

a, z = 2 a^{3} - 4 b c

a, y = 3 a^{3}

What are the solutions to the equation 2x^3+7x^2+2x-3=0 ?
The solutions to the equation 2x^3+7x^2+2x-3=0 are x=-1,x= 1/2 ,x=-3
Find the zeros of 2x^3+7x^2+2x-3=0
The zeros of 2x^3+7x^2+2x-3=0 are x=-1,x= 1/2 ,x=-3