What are the solutions to the equation (2x+2)(3x-6)(4x+12)=0 ?

The solutions to the equation (2x+2)(3x-6)(4x+12)=0 are x=-1,x=2,x=-3

Find the zeros of (2x+2)(3x-6)(4x+12)=0

The zeros of (2x+2)(3x-6)(4x+12)=0 are x=-1,x=2,x=-3

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(2 x + 2) (3 x - 6) (4 x + 12) = 0

x = - 1, x = 2, x = - 3

Solution steps

(2 x + 2) (3 x - 6) (4 x + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 2 = 0 or 3 x - 6 = 0 or 4 x + 12 = 0

Solve

2 x + 2 = 0 : x = - 1

Solve

3 x - 6 = 0 : x = 2

Solve

4 x + 12 = 0 : x = - 3

The solutions are

x = - 1, x = 2, x = - 3

(x^{2} + 2) (x^{2} - 12) = 72

- 5 + 4 m^{3} = 103

- 6 x^{4} + 8 x^{2} + 2 = 0

x^{3} - x^{2} + 3 x - 3 = 0

x, x^{3} + 4 x^{2} - 10 = 0

What are the solutions to the equation (2x+2)(3x-6)(4x+12)=0 ?
The solutions to the equation (2x+2)(3x-6)(4x+12)=0 are x=-1,x=2,x=-3
Find the zeros of (2x+2)(3x-6)(4x+12)=0
The zeros of (2x+2)(3x-6)(4x+12)=0 are x=-1,x=2,x=-3