What are the solutions to the equation 10=-c^3+9 ?

The solutions to the equation 10=-c^3+9 are c=-1,c= 1/2-(sqrt(3))/2 i,c= 1/2+(sqrt(3))/2 i

Find the zeros of 10=-c^3+9

The zeros of 10=-c^3+9 are c=-1,c= 1/2-(sqrt(3))/2 i,c= 1/2+(sqrt(3))/2 i

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10 = - c^{3} + 9

c = - 1, c = \frac{1}{2} - \frac{3}{2} i, c = \frac{1}{2} + \frac{3}{2} i

Solution steps

10 = - c^{3} + 9

Switch sides

- c^{3} + 9 = 10

Move

9

to the right side

- c^{3} = 1

Divide both sides by

- 1

c^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

c = - 1, c = \frac{1}{2} - \frac{3}{2} i, c = \frac{1}{2} + \frac{3}{2} i

\frac{( 4 x - 7 ) ^{3}}{3} = 27

x^{4} = - 9

2 x^{3} + x^{2} - x + 6 = 0

x^{4} = 13

z^{3} - 8 z^{2} + 15 z = 0

What are the solutions to the equation 10=-c^3+9 ?
The solutions to the equation 10=-c^3+9 are c=-1,c= 1/2-(sqrt(3))/2 i,c= 1/2+(sqrt(3))/2 i
Find the zeros of 10=-c^3+9
The zeros of 10=-c^3+9 are c=-1,c= 1/2-(sqrt(3))/2 i,c= 1/2+(sqrt(3))/2 i