What are the solutions to the equation 2x^2-5x-52=0 ?

The solutions to the equation 2x^2-5x-52=0 are x= 13/2 ,x=-4

Find the zeros of 2x^2-5x-52=0

The zeros of 2x^2-5x-52=0 are x= 13/2 ,x=-4

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2 x^{2} - 5 x - 52 = 0

x = \frac{13}{2}, x = - 4

Decimal Notation

x = 6.5, x = - 4

Solution steps

2 x^{2} - 5 x - 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 52 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 52) = 21

x_{1, 2} = \frac{- ( - 5 ) \pm 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 21}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 21}{2 \cdot 2}

x = \frac{- ( - 5 ) + 21}{2 \cdot 2} : \frac{13}{2}

x = \frac{- ( - 5 ) - 21}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{13}{2}, x = - 4

2 (4 x - 5) = 7 x

w^{3} - 64

\frac{1}{2} x + 10 = 4

1 + 4 x \leq 5 - 2 x

\frac{4 x - 5}{7 x} < 2

What are the solutions to the equation 2x^2-5x-52=0 ?
The solutions to the equation 2x^2-5x-52=0 are x= 13/2 ,x=-4
Find the zeros of 2x^2-5x-52=0
The zeros of 2x^2-5x-52=0 are x= 13/2 ,x=-4