What are the solutions to the equation 180x^3+36x^2-5x-1=0 ?

The solutions to the equation 180x^3+36x^2-5x-1=0 are x=-1/5 ,x=-1/6 ,x= 1/6

Find the zeros of 180x^3+36x^2-5x-1=0

The zeros of 180x^3+36x^2-5x-1=0 are x=-1/5 ,x=-1/6 ,x= 1/6

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180 x^{3} + 36 x^{2} - 5 x - 1 = 0

x = - \frac{1}{5}, x = - \frac{1}{6}, x = \frac{1}{6}

Decimal Notation

x = - 0.2, x = - 0.16666 \dots, x = 0.16666 \dots

Solution steps

180 x^{3} + 36 x^{2} - 5 x - 1 = 0

Factor

180 x^{3} + 36 x^{2} - 5 x - 1 : (5 x + 1) (6 x + 1) (6 x - 1)

(5 x + 1) (6 x + 1) (6 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 1 = 0 or 6 x + 1 = 0 or 6 x - 1 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

6 x + 1 = 0 : x = - \frac{1}{6}

Solve

6 x - 1 = 0 : x = \frac{1}{6}

The solutions are

x = - \frac{1}{5}, x = - \frac{1}{6}, x = \frac{1}{6}

x^{3} + 25.3 x^{2} + 219 x + 660.1 = 0

x^{4} - 6 x^{3} + 13 x^{2} - 12 x + 4 = 0

z^{3} = - 2 - 23 i

x^{3} - 6 x^{2} + 7 x + 4 = 0

x^{3} = 0.027

What are the solutions to the equation 180x^3+36x^2-5x-1=0 ?
The solutions to the equation 180x^3+36x^2-5x-1=0 are x=-1/5 ,x=-1/6 ,x= 1/6
Find the zeros of 180x^3+36x^2-5x-1=0
The zeros of 180x^3+36x^2-5x-1=0 are x=-1/5 ,x=-1/6 ,x= 1/6