What are the solutions to the equation 143=8-5y^3 ?

The solutions to the equation 143=8-5y^3 are y=-3,y= 3/2-(3sqrt(3))/2 i,y= 3/2+(3sqrt(3))/2 i

Find the zeros of 143=8-5y^3

The zeros of 143=8-5y^3 are y=-3,y= 3/2-(3sqrt(3))/2 i,y= 3/2+(3sqrt(3))/2 i

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143 = 8 - 5 y^{3}

y = - 3, y = \frac{3}{2} - \frac{3 3}{2} i, y = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

143 = 8 - 5 y^{3}

Switch sides

8 - 5 y^{3} = 143

Move

8

to the right side

- 5 y^{3} = 135

Divide both sides by

- 5

y^{3} = - 27

For

x^{3} = f (a)

the solutions are

Simplify

y = - 3, y = \frac{3}{2} - \frac{3 3}{2} i, y = \frac{3}{2} + \frac{3 3}{2} i

5 x^{3} - 80 x = 0

4 x^{3} - 20 x - 7 = 0

s^{3} + 82 s^{2} + 304 s + 11520 = 0

2 x^{3} + 14 x^{2} - 14 x - 98 = 0

5 x^{4} = - 10 i

What are the solutions to the equation 143=8-5y^3 ?
The solutions to the equation 143=8-5y^3 are y=-3,y= 3/2-(3sqrt(3))/2 i,y= 3/2+(3sqrt(3))/2 i
Find the zeros of 143=8-5y^3
The zeros of 143=8-5y^3 are y=-3,y= 3/2-(3sqrt(3))/2 i,y= 3/2+(3sqrt(3))/2 i