What are the solutions to the equation (+x^2)(x-5)=1 ?

The solutions to the equation (+x^2)(x-5)=1 are x\approx 5.03937…

Find the zeros of (+x^2)(x-5)=1

The zeros of (+x^2)(x-5)=1 are x\approx 5.03937…

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(+ x^{2}) (x - 5) = 1

x \approx 5.03937 \dots

Solution steps

(x^{2}) (x - 5) = 1

Expand

(x^{2}) (x - 5) : x^{3} - 5 x^{2}

x^{3} - 5 x^{2} = 1

Move

1

to the left side

x^{3} - 5 x^{2} - 1 = 0

Find one solution for

x^{3} - 5 x^{2} - 1 = 0

using Newton-Raphson:

No Solution for

x \in R

x \approx 5.03937 \dots

The solution is

x \approx 5.03937 \dots

x^{4} - 12 x^{3} + 36 x^{2} = 0

x^{4} + 24 = 14 x^{2}

3 z^{3} - 3 z^{2} = - 4 z + 4

3 x^{3} = x

(x + 5)^{2} (x - 2) = 0

What are the solutions to the equation (+x^2)(x-5)=1 ?
The solutions to the equation (+x^2)(x-5)=1 are x\approx 5.03937…
Find the zeros of (+x^2)(x-5)=1
The zeros of (+x^2)(x-5)=1 are x\approx 5.03937…