What are the solutions to the equation 216x^3-1=0 ?

The solutions to the equation 216x^3-1=0 are x= 1/6 ,x=-1/12+1/(4sqrt(3))i,x=-1/12-1/(4sqrt(3))i

Find the zeros of 216x^3-1=0

The zeros of 216x^3-1=0 are x= 1/6 ,x=-1/12+1/(4sqrt(3))i,x=-1/12-1/(4sqrt(3))i

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216 x^{3} - 1 = 0

x = \frac{1}{6}, x = - \frac{1}{12} + \frac{1}{4 3} i, x = - \frac{1}{12} - \frac{1}{4 3} i

Solution steps

216 x^{3} - 1 = 0

Move

1

to the right side

216 x^{3} = 1

Divide both sides by

216

x^{3} = \frac{1}{216}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{1}{6}, x = - \frac{1}{12} + \frac{1}{4 3} i, x = - \frac{1}{12} - \frac{1}{4 3} i

m^{3} = 0.027

2 x^{2} - x^{3} = 0

15 x^{4} + 240 x^{2} + 225 = 0

2 x^{3} = 4 x^{2} - 2 x

1 - 3 (x - 4)^{3} = 25

What are the solutions to the equation 216x^3-1=0 ?
The solutions to the equation 216x^3-1=0 are x= 1/6 ,x=-1/12+1/(4sqrt(3))i,x=-1/12-1/(4sqrt(3))i
Find the zeros of 216x^3-1=0
The zeros of 216x^3-1=0 are x= 1/6 ,x=-1/12+1/(4sqrt(3))i,x=-1/12-1/(4sqrt(3))i