What are the solutions to the equation 3x^3-16x^2+23x-6=0 ?

The solutions to the equation 3x^3-16x^2+23x-6=0 are x=2,x= 1/3 ,x=3

Find the zeros of 3x^3-16x^2+23x-6=0

The zeros of 3x^3-16x^2+23x-6=0 are x=2,x= 1/3 ,x=3

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3 x^{3} - 16 x^{2} + 23 x - 6 = 0

x = 2, x = \frac{1}{3}, x = 3

Decimal Notation

x = 2, x = 0.33333 \dots, x = 3

Solution steps

3 x^{3} - 16 x^{2} + 23 x - 6 = 0

Factor

3 x^{3} - 16 x^{2} + 23 x - 6 : (x - 2) (3 x - 1) (x - 3)

(x - 2) (3 x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x - 1 = 0 or x - 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x - 3 = 0 : x = 3

The solutions are

x = 2, x = \frac{1}{3}, x = 3

x, 4 x^{3} - 8 x^{2} - x + 2 = 0

1000 (1 + x)^{12} = 2000

(x (x + 1) (x - 1)) 3 = 2 x - 2

2 x^{4} - x^{2} - 15 = 0

3 x^{4} + 4 x^{3} - x^{2} = x^{2}

What are the solutions to the equation 3x^3-16x^2+23x-6=0 ?
The solutions to the equation 3x^3-16x^2+23x-6=0 are x=2,x= 1/3 ,x=3
Find the zeros of 3x^3-16x^2+23x-6=0
The zeros of 3x^3-16x^2+23x-6=0 are x=2,x= 1/3 ,x=3