What are the solutions to the equation (x+3)^2+8(x+3)-9=0 ?

The solutions to the equation (x+3)^2+8(x+3)-9=0 are x=-2,x=-12

Find the zeros of (x+3)^2+8(x+3)-9=0

The zeros of (x+3)^2+8(x+3)-9=0 are x=-2,x=-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 3)^{2} + 8 (x + 3) - 9 = 0

x = - 2, x = - 12

Solution steps

(x + 3)^{2} + 8 (x + 3) - 9 = 0

Expand

(x + 3)^{2} + 8 (x + 3) - 9 : x^{2} + 14 x + 24

x^{2} + 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 24 = 10

x_{1, 2} = \frac{- 14 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 10}{2 \cdot 1}, x_{2} = \frac{- 14 - 10}{2 \cdot 1}

x = \frac{- 14 + 10}{2 \cdot 1} : - 2

x = \frac{- 14 - 10}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 2, x = - 12

x - 7 > - 11

(x - 6) (x + 8) 2 - (x - 6) 2 (x + 8)

y^{2} - 4 y

x^{2} + 4

103 h = 7 (\frac{2}{7} - \frac{3}{7} h) - 103

What are the solutions to the equation (x+3)^2+8(x+3)-9=0 ?
The solutions to the equation (x+3)^2+8(x+3)-9=0 are x=-2,x=-12
Find the zeros of (x+3)^2+8(x+3)-9=0
The zeros of (x+3)^2+8(x+3)-9=0 are x=-2,x=-12