What are the solutions to the equation z(z+9)(4z+2)=0 ?

The solutions to the equation z(z+9)(4z+2)=0 are z=0,z=-9,z=-1/2

Find the zeros of z(z+9)(4z+2)=0

The zeros of z(z+9)(4z+2)=0 are z=0,z=-9,z=-1/2

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z (z + 9) (4 z + 2) = 0

z = 0, z = - 9, z = - \frac{1}{2}

Decimal Notation

z = 0, z = - 9, z = - 0.5

Solution steps

z (z + 9) (4 z + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

z = 0 or z + 9 = 0 or 4 z + 2 = 0

Solve

z + 9 = 0 : z = - 9

Solve

4 z + 2 = 0 : z = - \frac{1}{2}

The solutions are

z = 0, z = - 9, z = - \frac{1}{2}

2 x^{3} + 7 x^{2} - 21 x - 54 = 0

30 x^{4} - 60 x^{2} = 0

10 x^{2} - x^{4} - 25 = 0

(x^{2} + 5 x + 25) (x - 5) - 5 = 86

x^{5} + 4 x + 1 = 0

What are the solutions to the equation z(z+9)(4z+2)=0 ?
The solutions to the equation z(z+9)(4z+2)=0 are z=0,z=-9,z=-1/2
Find the zeros of z(z+9)(4z+2)=0
The zeros of z(z+9)(4z+2)=0 are z=0,z=-9,z=-1/2