What are the solutions to the equation (x^2-6)(x^2+1)=0 ?

The solutions to the equation (x^2-6)(x^2+1)=0 are x=i,x=-i,x=-sqrt(6),x=sqrt(6)

Find the zeros of (x^2-6)(x^2+1)=0

The zeros of (x^2-6)(x^2+1)=0 are x=i,x=-i,x=-sqrt(6),x=sqrt(6)

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(x^{2} - 6) (x^{2} + 1) = 0

x = i, x = - i, x = - 6, x = 6

Solution steps

(x^{2} - 6) (x^{2} + 1) = 0

Factor

(x^{2} - 6) (x^{2} + 1) : (x^{2} + 1) (x + 6) (x - 6)

(x^{2} + 1) (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0 or x + 6 = 0 or x - 6 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = i, x = - i, x = - 6, x = 6

x^{10} + 3 (2 x - 4) = 17 - (x + 5)

x^{4} + 16 = 2 x^{3} + 8 x

4 x^{3} + 8 x^{2} - 9 x = 18

x^{2} (2 x^{2} + 6) = 8

1331 x^{3} - 216 = 0

What are the solutions to the equation (x^2-6)(x^2+1)=0 ?
The solutions to the equation (x^2-6)(x^2+1)=0 are x=i,x=-i,x=-sqrt(6),x=sqrt(6)
Find the zeros of (x^2-6)(x^2+1)=0
The zeros of (x^2-6)(x^2+1)=0 are x=i,x=-i,x=-sqrt(6),x=sqrt(6)