What are the solutions to the equation -x^3+6x^2-5x-12=0 ?

The solutions to the equation -x^3+6x^2-5x-12=0 are x=-1,x=3,x=4

Find the zeros of -x^3+6x^2-5x-12=0

The zeros of -x^3+6x^2-5x-12=0 are x=-1,x=3,x=4

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- x^{3} + 6 x^{2} - 5 x - 12 = 0

x = - 1, x = 3, x = 4

Solution steps

- x^{3} + 6 x^{2} - 5 x - 12 = 0

Factor

- x^{3} + 6 x^{2} - 5 x - 12 : - (x + 1) (x - 3) (x - 4)

- (x + 1) (x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = 3, x = 4

x^{6} + 64 x^{4} = 0

x^{3} + 2 x^{2} - 35 x = 0

x^{4} + 38 = 102

x^{6} - 3 x^{4} + 3 x^{2} - 1 = 0

2 n + 28 = n^{3}

What are the solutions to the equation -x^3+6x^2-5x-12=0 ?
The solutions to the equation -x^3+6x^2-5x-12=0 are x=-1,x=3,x=4
Find the zeros of -x^3+6x^2-5x-12=0
The zeros of -x^3+6x^2-5x-12=0 are x=-1,x=3,x=4