What are the solutions to the equation x^3+7x^2+24x+18=0 ?

The solutions to the equation x^3+7x^2+24x+18=0 are x=-1,x=-3+3i,x=-3-3i

Find the zeros of x^3+7x^2+24x+18=0

The zeros of x^3+7x^2+24x+18=0 are x=-1,x=-3+3i,x=-3-3i

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x^{3} + 7 x^{2} + 24 x + 18 = 0

x = - 1, x = - 3 + 3 i, x = - 3 - 3 i

Solution steps

x^{3} + 7 x^{2} + 24 x + 18 = 0

Factor

x^{3} + 7 x^{2} + 24 x + 18 : (x + 1) (x^{2} + 6 x + 18)

(x + 1) (x^{2} + 6 x + 18) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 6 x + 18 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 6 x + 18 = 0 : x = - 3 + 3 i, x = - 3 - 3 i

The solutions are

x = - 1, x = - 3 + 3 i, x = - 3 - 3 i

x^{5} = 4 x^{3}

x^{3} - 3 x^{2} + x + 5 = 0

x - 2 x^{2} = 1 + x^{5}

x, x^{4} - 6 x^{2} + 5 = 0

3 (36 x^{2} - 49) (x^{2} + 64) = 0

What are the solutions to the equation x^3+7x^2+24x+18=0 ?
The solutions to the equation x^3+7x^2+24x+18=0 are x=-1,x=-3+3i,x=-3-3i
Find the zeros of x^3+7x^2+24x+18=0
The zeros of x^3+7x^2+24x+18=0 are x=-1,x=-3+3i,x=-3-3i