What are the solutions to the equation 2x^2-4x=3 ?

The solutions to the equation 2x^2-4x=3 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

Find the zeros of 2x^2-4x=3

The zeros of 2x^2-4x=3 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2

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2 x^{2} - 4 x = 3

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

Decimal

x = 2.58113 \dots, x = - 0.58113 \dots

Solution steps

2 x^{2} - 4 x = 3

Move

3

to the left side

2 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 3) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 2} : \frac{2 + 10}{2}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 2} : \frac{2 - 10}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{2}, x = \frac{2 - 10}{2}

\frac{x + 3}{x - 2} < 1

24 3^{\frac{7}{10}} \cdot 24 3^{\frac{1}{10}}

3 n - 7 < 26

x^{3} - 729

18 x^{4 p + m} - 66 x^{2 p + m} y^{2} - 24 x^{m} y^{4}

What are the solutions to the equation 2x^2-4x=3 ?
The solutions to the equation 2x^2-4x=3 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2
Find the zeros of 2x^2-4x=3
The zeros of 2x^2-4x=3 are x=(2+sqrt(10))/2 ,x=(2-sqrt(10))/2