What are the solutions to the equation xx(x+1)-2(x+1)=0 ?

The solutions to the equation xx(x+1)-2(x+1)=0 are x=-1,x=-sqrt(2),x=sqrt(2)

Find the zeros of xx(x+1)-2(x+1)=0

The zeros of xx(x+1)-2(x+1)=0 are x=-1,x=-sqrt(2),x=sqrt(2)

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xx (x + 1) - 2 (x + 1) = 0

x = - 1, x = - 2, x = 2

Decimal Notation

x = - 1, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

xx (x + 1) - 2 (x + 1) = 0

Factor

xx (x + 1) - 2 (x + 1) : (x + 1) (x + 2) (x - 2)

(x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = - 2, x = 2

c^{3} - c = 0

3 x^{3} + 2 x^{3} = 5 x^{6}

4 x^{4} - 12 x^{2} + 5 = 0

(x + 1) (x - 2) (x - 3) = 0

x^{4} + x^{2} + 16 = 0

What are the solutions to the equation xx(x+1)-2(x+1)=0 ?
The solutions to the equation xx(x+1)-2(x+1)=0 are x=-1,x=-sqrt(2),x=sqrt(2)
Find the zeros of xx(x+1)-2(x+1)=0
The zeros of xx(x+1)-2(x+1)=0 are x=-1,x=-sqrt(2),x=sqrt(2)