What are the solutions to the equation -x^3+3x^2-2=0 ?

The solutions to the equation -x^3+3x^2-2=0 are x=1,x=1+sqrt(3),x=1-sqrt(3)

Find the zeros of -x^3+3x^2-2=0

The zeros of -x^3+3x^2-2=0 are x=1,x=1+sqrt(3),x=1-sqrt(3)

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- x^{3} + 3 x^{2} - 2 = 0

x = 1, x = 1 + 3, x = 1 - 3

Decimal Notation

x = 1, x = 2.73205 \dots, x = - 0.73205 \dots

Solution steps

- x^{3} + 3 x^{2} - 2 = 0

Factor

- x^{3} + 3 x^{2} - 2 : - (x - 1) (x^{2} - 2 x - 2)

- (x - 1) (x^{2} - 2 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 2 x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 2 x - 2 = 0 : x = 1 + 3, x = 1 - 3

The solutions are

x = 1, x = 1 + 3, x = 1 - 3

20 x^{3} - 12 x^{2} - 20 x = 0

4 t^{3} + 4 t^{2} - 2 t = 0

2 x^{4} + 17 x^{3} + 43 x^{2} + 37 x + 6 = 0

4 x^{4} - 13 x + 3 = 0

- 4 x^{3} + 6 x^{2} = 0

What are the solutions to the equation -x^3+3x^2-2=0 ?
The solutions to the equation -x^3+3x^2-2=0 are x=1,x=1+sqrt(3),x=1-sqrt(3)
Find the zeros of -x^3+3x^2-2=0
The zeros of -x^3+3x^2-2=0 are x=1,x=1+sqrt(3),x=1-sqrt(3)