What are the solutions to the equation -2x^4+9=3x+5 ?

The solutions to the equation -2x^4+9=3x+5 are x\approx 0.89861…,x\approx-1.42639…

Find the zeros of -2x^4+9=3x+5

The zeros of -2x^4+9=3x+5 are x\approx 0.89861…,x\approx-1.42639…

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- 2 x^{4} + 9 = 3 x + 5

x \approx 0.89861 \dots, x \approx - 1.42639 \dots

Solution steps

- 2 x^{4} + 9 = 3 x + 5

Move

5

to the left side

- 2 x^{4} + 4 = 3 x

Move

3 x

to the left side

- 2 x^{4} + 4 - 3 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 2 x^{4} - 3 x + 4 = 0

Find one solution for

- 2 x^{4} - 3 x + 4 = 0

using Newton-Raphson:

x \approx 0.89861 \dots

Apply long division:

\frac{- 2 x ^{4} - 3 x + 4}{x - 0.89861 \dots} = - 2 x^{3} - 1.79723 \dots x^{2} - 1.61502 \dots x - 4.45128 \dots

- 2 x^{3} - 1.79723 \dots x^{2} - 1.61502 \dots x - 4.45128 \dots \approx 0

Find one solution for

- 2 x^{3} - 1.79723 \dots x^{2} - 1.61502 \dots x - 4.45128 \dots = 0

using Newton-Raphson:

x \approx - 1.42639 \dots

Apply long division:

\frac{- 2 x ^{3} - 1.79723 \dots x ^{2} - 1.61502 \dots x - 4.45128 \dots}{x + 1.42639 \dots} = - 2 x^{2} + 1.05555 \dots x - 3.12065 \dots

- 2 x^{2} + 1.05555 \dots x - 3.12065 \dots \approx 0

Find one solution for

- 2 x^{2} + 1.05555 \dots x - 3.12065 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solutions are

x \approx 0.89861 \dots, x \approx - 1.42639 \dots

2 x^{3} + 7 x^{2} - 12 x - 42 = 0

2 x^{3} + x - 3 = 0

x, x^{3} + y^{3} = 126

x^{3} = - 10

x^{3} = - 15

What are the solutions to the equation -2x^4+9=3x+5 ?
The solutions to the equation -2x^4+9=3x+5 are x\approx 0.89861…,x\approx-1.42639…
Find the zeros of -2x^4+9=3x+5
The zeros of -2x^4+9=3x+5 are x\approx 0.89861…,x\approx-1.42639…