What are the solutions to the equation 1800-1505x^2+118x^4=0 ?

The solutions to the equation 1800-1505x^2+118x^4=0 are

Find the zeros of 1800-1505x^2+118x^4=0

The zeros of 1800-1505x^2+118x^4=0 are

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1800 - 1505 x^{2} + 118 x^{4} = 0

x = \frac{1505 + 5 56617}{2 59}, x = - \frac{1505 + 5 56617}{2 59}, x = \frac{1505 - 5 56617}{2 59}, x = - \frac{1505 - 5 56617}{2 59}

Decimal Notation

x = 3.37909 \dots, x = - 3.37909 \dots, x = 1.15583 \dots, x = - 1.15583 \dots

Solution steps

1800 - 1505 x^{2} + 118 x^{4} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

118 x^{4} - 1505 x^{2} + 1800 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

118 u^{2} - 1505 u + 1800 = 0

Solve

118 u^{2} - 1505 u + 1800 = 0 : u = \frac{1505 + 5 56617}{236}, u = \frac{1505 - 5 56617}{236}

u = \frac{1505 + 5 56617}{236}, u = \frac{1505 - 5 56617}{236}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{1505 + 5 56617}{236} : x = \frac{1505 + 5 56617}{2 59}, x = - \frac{1505 + 5 56617}{2 59}

Solve

x^{2} = \frac{1505 - 5 56617}{236} : x = \frac{1505 - 5 56617}{2 59}, x = - \frac{1505 - 5 56617}{2 59}

The solutions are

x = \frac{1505 + 5 56617}{2 59}, x = - \frac{1505 + 5 56617}{2 59}, x = \frac{1505 - 5 56617}{2 59}, x = - \frac{1505 - 5 56617}{2 59}

(x^{2} - 7) (x - 1) = 0

x^{3} - 9 x^{2} - 4 x + 36 = 0

(x - 1)^{5} = - 32

x^{3} + 3 x - 10 = 0

9 t - t^{3} = 0

What are the solutions to the equation 1800-1505x^2+118x^4=0 ?
The solutions to the equation 1800-1505x^2+118x^4=0 are
Find the zeros of 1800-1505x^2+118x^4=0
The zeros of 1800-1505x^2+118x^4=0 are