What are the solutions to the equation 3x^3+3x^2+x=122 ?

The solutions to the equation 3x^3+3x^2+x=122 are x\approx 3.10655…

Find the zeros of 3x^3+3x^2+x=122

The zeros of 3x^3+3x^2+x=122 are x\approx 3.10655…

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3 x^{3} + 3 x^{2} + x = 122

x \approx 3.10655 \dots

Solution steps

3 x^{3} + 3 x^{2} + x = 122

Move

122

to the left side

3 x^{3} + 3 x^{2} + x - 122 = 0

Find one solution for

3 x^{3} + 3 x^{2} + x - 122 = 0

using Newton-Raphson:

x \approx 3.10655 \dots

Apply long division:

\frac{3 x ^{3} + 3 x ^{2} + x - 122}{x - 3.10655 \dots} = 3 x^{2} + 12.31967 \dots x + 39.27176 \dots

3 x^{2} + 12.31967 \dots x + 39.27176 \dots \approx 0

Find one solution for

3 x^{2} + 12.31967 \dots x + 39.27176 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 3.10655 \dots

x^{3} = 120

x^{3} = 160

- 15 z + 41 z^{2} - 14 z^{3} = 0

\frac{4}{5} = 2500 r^{5}

x^{3} - 3 x^{2} - 18 x + 40 = 0

What are the solutions to the equation 3x^3+3x^2+x=122 ?
The solutions to the equation 3x^3+3x^2+x=122 are x\approx 3.10655…
Find the zeros of 3x^3+3x^2+x=122
The zeros of 3x^3+3x^2+x=122 are x\approx 3.10655…