What are the solutions to the equation 3x^2-2.4x+0.41=0 ?

The solutions to the equation 3x^2-2.4x+0.41=0 are x=(12+sqrt(21))/(30),x=(12-sqrt(21))/(30)

Find the zeros of 3x^2-2.4x+0.41=0

The zeros of 3x^2-2.4x+0.41=0 are x=(12+sqrt(21))/(30),x=(12-sqrt(21))/(30)

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3 x^{2} - 2.4 x + 0.41 = 0

x = \frac{12 + 21}{30}, x = \frac{12 - 21}{30}

Decimal Notation

x = 0.55275 \dots, x = 0.24724 \dots

Solution steps

3 x^{2} - 2.4 x + 0.41 = 0

Multiply both sides by

100

300 x^{2} - 240 x + 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 240 ) \pm ( - 240 ) ^{2} - 4 \cdot 300 \cdot 41}{2 \cdot 300}

(- 240)^{2} - 4 \cdot 300 \cdot 41 = 2021

x_{1, 2} = \frac{- ( - 240 ) \pm 20 21}{2 \cdot 300}

Separate the solutions

x_{1} = \frac{- ( - 240 ) + 20 21}{2 \cdot 300}, x_{2} = \frac{- ( - 240 ) - 20 21}{2 \cdot 300}

x = \frac{- ( - 240 ) + 20 21}{2 \cdot 300} : \frac{12 + 21}{30}

x = \frac{- ( - 240 ) - 20 21}{2 \cdot 300} : \frac{12 - 21}{30}

The solutions to the quadratic equation are:

x = \frac{12 + 21}{30}, x = \frac{12 - 21}{30}

3 0^{4}

\frac{15 x y}{3 10 x y ^{3}}

(x - 4)^{\frac{2}{3}} < (2 x)^{\frac{1}{3}}

x - 6 < 4

What are the solutions to the equation 3x^2-2.4x+0.41=0 ?
The solutions to the equation 3x^2-2.4x+0.41=0 are x=(12+sqrt(21))/(30),x=(12-sqrt(21))/(30)
Find the zeros of 3x^2-2.4x+0.41=0
The zeros of 3x^2-2.4x+0.41=0 are x=(12+sqrt(21))/(30),x=(12-sqrt(21))/(30)