What are the solutions to the equation 20=(5+((0.12x)/(10)))^{20} ?

The solutions to the equation 20=(5+((0.12x)/(10)))^{20} are x=-319.86780…,x=-513.46552…

Find the zeros of 20=(5+((0.12x)/(10)))^{20}

The zeros of 20=(5+((0.12x)/(10)))^{20} are x=-319.86780…,x=-513.46552…

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20 = (5 + (\frac{0.12 x}{10}))^{20}

x = - 319.86780 \dots, x = - 513.46552 \dots

Solution steps

20 = (5 + (\frac{0.12 x}{10}))^{20}

Switch sides

(5 + (\frac{0.12 x}{10}))^{20} = 20

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = - 319.86780 \dots, x = - 513.46552 \dots

8 x^{3} - 8 x^{2} + 1 = 0

x^{3} - 7 = 0

\frac{x ^{3}}{2} = 8

- 8 + 3 X^{3} + 2 X = 0

- x^{4} + 2 = x^{2}

What are the solutions to the equation 20=(5+((0.12x)/(10)))^{20} ?
The solutions to the equation 20=(5+((0.12x)/(10)))^{20} are x=-319.86780…,x=-513.46552…
Find the zeros of 20=(5+((0.12x)/(10)))^{20}
The zeros of 20=(5+((0.12x)/(10)))^{20} are x=-319.86780…,x=-513.46552…