What are the solutions to the equation 3x^3+4x^2-x-2=0 ?

The solutions to the equation 3x^3+4x^2-x-2=0 are x=-1,x= 2/3

Find the zeros of 3x^3+4x^2-x-2=0

The zeros of 3x^3+4x^2-x-2=0 are x=-1,x= 2/3

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3 x^{3} + 4 x^{2} - x - 2 = 0

x = - 1, x = \frac{2}{3}

Decimal Notation

x = - 1, x = 0.66666 \dots

Solution steps

3 x^{3} + 4 x^{2} - x - 2 = 0

Factor

3 x^{3} + 4 x^{2} - x - 2 : (x + 1)^{2} (3 x - 2)

(x + 1)^{2} (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions are

x = - 1, x = \frac{2}{3}

2 + x^{3} = 18

27 x^{3} - 18 x^{2} - 3 x + 2 = 0

4 x^{3} - 4 x^{2} + x = 0

x^{2} 4 x - 5 = 0

x^{3} + 12 = 14

What are the solutions to the equation 3x^3+4x^2-x-2=0 ?
The solutions to the equation 3x^3+4x^2-x-2=0 are x=-1,x= 2/3
Find the zeros of 3x^3+4x^2-x-2=0
The zeros of 3x^3+4x^2-x-2=0 are x=-1,x= 2/3