What are the solutions to the equation 1/8 =z^3 ?

The solutions to the equation 1/8 =z^3 are z= 1/2 ,z=-1/4+(sqrt(3))/4 i,z=-1/4-(sqrt(3))/4 i

Find the zeros of 1/8 =z^3

The zeros of 1/8 =z^3 are z= 1/2 ,z=-1/4+(sqrt(3))/4 i,z=-1/4-(sqrt(3))/4 i

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\frac{1}{8} = z^{3}

z = \frac{1}{2}, z = - \frac{1}{4} + \frac{3}{4} i, z = - \frac{1}{4} - \frac{3}{4} i

Solution steps

\frac{1}{8} = z^{3}

Switch sides

z^{3} = \frac{1}{8}

For

x^{3} = f (a)

the solutions are

Simplify

z = \frac{1}{2}, z = - \frac{1}{4} + \frac{3}{4} i, z = - \frac{1}{4} - \frac{3}{4} i

x - 13 + x^{4} = 2

x^{6} + 5 = 13 - x

- 4 x^{3} + 36 x = 0

x^{3} + x^{2} - 120 = 0

2 x^{4} - 5 0^{2} = 0

What are the solutions to the equation 1/8 =z^3 ?
The solutions to the equation 1/8 =z^3 are z= 1/2 ,z=-1/4+(sqrt(3))/4 i,z=-1/4-(sqrt(3))/4 i
Find the zeros of 1/8 =z^3
The zeros of 1/8 =z^3 are z= 1/2 ,z=-1/4+(sqrt(3))/4 i,z=-1/4-(sqrt(3))/4 i