What are the solutions to the equation 16x^3-32x^2-4x+8=0 ?

The solutions to the equation 16x^3-32x^2-4x+8=0 are x=2,x=-1/2 ,x= 1/2

Find the zeros of 16x^3-32x^2-4x+8=0

The zeros of 16x^3-32x^2-4x+8=0 are x=2,x=-1/2 ,x= 1/2

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16 x^{3} - 32 x^{2} - 4 x + 8 = 0

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 2, x = - 0.5, x = 0.5

Solution steps

16 x^{3} - 32 x^{2} - 4 x + 8 = 0

Factor

16 x^{3} - 32 x^{2} - 4 x + 8 : 4 (x - 2) (2 x + 1) (2 x - 1)

4 (x - 2) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

- λ^{3} + 4 λ^{2} - 3 λ = 0

x (x - 5) (x - 7) = x (7 - x)

x^{3} - 5 x^{2} - 25 x = - 125

x^{3} - 3 x + 8 = - 3 x

0 = x^{3} - 27

What are the solutions to the equation 16x^3-32x^2-4x+8=0 ?
The solutions to the equation 16x^3-32x^2-4x+8=0 are x=2,x=-1/2 ,x= 1/2
Find the zeros of 16x^3-32x^2-4x+8=0
The zeros of 16x^3-32x^2-4x+8=0 are x=2,x=-1/2 ,x= 1/2