What are the solutions to the equation 3x^2+12x+21=9 ?

The solutions to the equation 3x^2+12x+21=9 are x=-2

Find the zeros of 3x^2+12x+21=9

The zeros of 3x^2+12x+21=9 are x=-2

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3 x^{2} + 12 x + 21 = 9

x = - 2

Solution steps

3 x^{2} + 12 x + 21 = 9

Move

9

to the left side

3 x^{2} + 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 12 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 3}

x = \frac{- 12}{2 \cdot 3}

\frac{- 12}{2 \cdot 3} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

(\frac{x ^{6}}{9 y ^{- 4}})^{- \frac{1}{2}}

200 - 72

\frac{3 a - 11}{5} = 8

(y + 18)^{2} = 77

4 (x - 3) = 8 (x - 1)

What are the solutions to the equation 3x^2+12x+21=9 ?
The solutions to the equation 3x^2+12x+21=9 are x=-2
Find the zeros of 3x^2+12x+21=9
The zeros of 3x^2+12x+21=9 are x=-2