What are the solutions to the equation 2x^3+13x^2+16x+5=0 ?

The solutions to the equation 2x^3+13x^2+16x+5=0 are x=-1,x=-1/2 ,x=-5

Find the zeros of 2x^3+13x^2+16x+5=0

The zeros of 2x^3+13x^2+16x+5=0 are x=-1,x=-1/2 ,x=-5

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2 x^{3} + 13 x^{2} + 16 x + 5 = 0

x = - 1, x = - \frac{1}{2}, x = - 5

Decimal Notation

x = - 1, x = - 0.5, x = - 5

Solution steps

2 x^{3} + 13 x^{2} + 16 x + 5 = 0

Factor

2 x^{3} + 13 x^{2} + 16 x + 5 : (x + 1) (2 x + 1) (x + 5)

(x + 1) (2 x + 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x + 1 = 0 or x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 1, x = - \frac{1}{2}, x = - 5

r^{4} - 2 r^{2} + 1 = 0

x^{3} - 4 x - 2 = 1

x^{3} - 1 = 1

(x^{2} - 5)^{2} - 3 (x^{2} - 5) = 4

x^{4} - x^{3} - 1 = 0

What are the solutions to the equation 2x^3+13x^2+16x+5=0 ?
The solutions to the equation 2x^3+13x^2+16x+5=0 are x=-1,x=-1/2 ,x=-5
Find the zeros of 2x^3+13x^2+16x+5=0
The zeros of 2x^3+13x^2+16x+5=0 are x=-1,x=-1/2 ,x=-5