What are the solutions to the equation m^3= 8/27 ?

The solutions to the equation m^3= 8/27 are m= 2/3 ,m=-1/3+1/(sqrt(3))i,m=-1/3-1/(sqrt(3))i

Find the zeros of m^3= 8/27

The zeros of m^3= 8/27 are m= 2/3 ,m=-1/3+1/(sqrt(3))i,m=-1/3-1/(sqrt(3))i

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m^{3} = \frac{8}{27}

m = \frac{2}{3}, m = - \frac{1}{3} + \frac{1}{3} i, m = - \frac{1}{3} - \frac{1}{3} i

Solution steps

m^{3} = \frac{8}{27}

For

x^{3} = f (a)

the solutions are

Simplify

m = \frac{2}{3}, m = - \frac{1}{3} + \frac{1}{3} i, m = - \frac{1}{3} - \frac{1}{3} i

3 x^{4} - 3 x = 0

25 x^{4} + 4 = 29 x^{2}

8 x^{3} + 3 x^{2} - 16 x - 1 = 0

x = x^{5}

n^{3} - n^{2} - 16 n - 20 = 0

What are the solutions to the equation m^3= 8/27 ?
The solutions to the equation m^3= 8/27 are m= 2/3 ,m=-1/3+1/(sqrt(3))i,m=-1/3-1/(sqrt(3))i
Find the zeros of m^3= 8/27
The zeros of m^3= 8/27 are m= 2/3 ,m=-1/3+1/(sqrt(3))i,m=-1/3-1/(sqrt(3))i