What are the solutions to the equation -x^3-6x^2+124x+264=0 ?

The solutions to the equation -x^3-6x^2+124x+264=0 are x=-2,x=2(sqrt(34)-1),x=-2(1+sqrt(34))

Find the zeros of -x^3-6x^2+124x+264=0

The zeros of -x^3-6x^2+124x+264=0 are x=-2,x=2(sqrt(34)-1),x=-2(1+sqrt(34))

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- x^{3} - 6 x^{2} + 124 x + 264 = 0

x = - 2, x = 2 (34 - 1), x = - 2 (1 + 34)

Solution steps

- x^{3} - 6 x^{2} + 124 x + 264 = 0

Factor

- x^{3} - 6 x^{2} + 124 x + 264 : - (x + 2) (x^{2} + 4 x - 132)

- (x + 2) (x^{2} + 4 x - 132) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 4 x - 132 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 4 x - 132 = 0 : x = 2 (34 - 1), x = - 2 (1 + 34)

The solutions are

x = - 2, x = 2 (34 - 1), x = - 2 (1 + 34)

3 m^{3} + 33 m^{2} + 90 m = 0

- 1 = 7 x^{3} + 1

2 x^{3} - 6 x^{2} + 6 x - 1 = - 5

t^{3} = d (2 + a)

x^{3} = \frac{8}{729}

What are the solutions to the equation -x^3-6x^2+124x+264=0 ?
The solutions to the equation -x^3-6x^2+124x+264=0 are x=-2,x=2(sqrt(34)-1),x=-2(1+sqrt(34))
Find the zeros of -x^3-6x^2+124x+264=0
The zeros of -x^3-6x^2+124x+264=0 are x=-2,x=2(sqrt(34)-1),x=-2(1+sqrt(34))