What are the solutions to the equation 2x^3+x^2-7x-6=0 ?

The solutions to the equation 2x^3+x^2-7x-6=0 are x=-1,x=-3/2 ,x=2

Find the zeros of 2x^3+x^2-7x-6=0

The zeros of 2x^3+x^2-7x-6=0 are x=-1,x=-3/2 ,x=2

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2 x^{3} + x^{2} - 7 x - 6 = 0

x = - 1, x = - \frac{3}{2}, x = 2

Decimal Notation

x = - 1, x = - 1.5, x = 2

Solution steps

2 x^{3} + x^{2} - 7 x - 6 = 0

Factor

2 x^{3} + x^{2} - 7 x - 6 : (x + 1) (2 x + 3) (x - 2)

(x + 1) (2 x + 3) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x + 3 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = - \frac{3}{2}, x = 2

x, y = 2 x^{3}

x^{3} - 3 x^{2} + 5 x - 10 = 0

x^{3} + 6 x^{2} + 5 x + 30 = 0

9 x^{5} - 36 x = 0

x^{3} - x^{2} - 4 x - 1 = 0

What are the solutions to the equation 2x^3+x^2-7x-6=0 ?
The solutions to the equation 2x^3+x^2-7x-6=0 are x=-1,x=-3/2 ,x=2
Find the zeros of 2x^3+x^2-7x-6=0
The zeros of 2x^3+x^2-7x-6=0 are x=-1,x=-3/2 ,x=2