What are the solutions to the equation 12x^3-48x^2+48x=0 ?

The solutions to the equation 12x^3-48x^2+48x=0 are x=0,x=2

Find the zeros of 12x^3-48x^2+48x=0

The zeros of 12x^3-48x^2+48x=0 are x=0,x=2

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12 x^{3} - 48 x^{2} + 48 x = 0

x = 0, x = 2

Solution steps

12 x^{3} - 48 x^{2} + 48 x = 0

Factor

12 x^{3} - 48 x^{2} + 48 x : 12 x (x - 2)^{2}

12 x (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2

2 x^{3} - x^{2} - 5 x - 2 = 0

2 x^{3} + 2 x + 1 = 0

x^{5} = 5

- 20 x^{3} + 216 x^{2} - 648 x + 432 = 0

24 x^{2} - 70 x - 2 x^{3} = 0

What are the solutions to the equation 12x^3-48x^2+48x=0 ?
The solutions to the equation 12x^3-48x^2+48x=0 are x=0,x=2
Find the zeros of 12x^3-48x^2+48x=0
The zeros of 12x^3-48x^2+48x=0 are x=0,x=2