What are the solutions to the equation x^3-x^2-4x-6=0 ?

The solutions to the equation x^3-x^2-4x-6=0 are x=3,x=-1+i,x=-1-i

Find the zeros of x^3-x^2-4x-6=0

The zeros of x^3-x^2-4x-6=0 are x=3,x=-1+i,x=-1-i

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x^{3} - x^{2} - 4 x - 6 = 0

x = 3, x = - 1 + i, x = - 1 - i

Solution steps

x^{3} - x^{2} - 4 x - 6 = 0

Factor

x^{3} - x^{2} - 4 x - 6 : (x - 3) (x^{2} + 2 x + 2)

(x - 3) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + 2 x + 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = 3, x = - 1 + i, x = - 1 - i

25 x^{4} = 74 x^{2} - 49

x^{4} - 3 x^{3} + 6 x^{2} - 12 x + 8 = 0

x^{5} - 2 x^{4} - 24 x^{3} = 0

x^{3} - 2 x - 2 = 1.5

2 x^{3} + 3 x^{2} + 8 x + 12 = 0

What are the solutions to the equation x^3-x^2-4x-6=0 ?
The solutions to the equation x^3-x^2-4x-6=0 are x=3,x=-1+i,x=-1-i
Find the zeros of x^3-x^2-4x-6=0
The zeros of x^3-x^2-4x-6=0 are x=3,x=-1+i,x=-1-i