What are the solutions to the equation v^3-2v^2-16v=-32 ?

The solutions to the equation v^3-2v^2-16v=-32 are v=2,v=-4,v=4

Find the zeros of v^3-2v^2-16v=-32

The zeros of v^3-2v^2-16v=-32 are v=2,v=-4,v=4

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v^{3} - 2 v^{2} - 16 v = - 32

v = 2, v = - 4, v = 4

Solution steps

v^{3} - 2 v^{2} - 16 v = - 32

Move

32

to the left side

v^{3} - 2 v^{2} - 16 v + 32 = 0

Factor

v^{3} - 2 v^{2} - 16 v + 32 : (v - 2) (v + 4) (v - 4)

(v - 2) (v + 4) (v - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v - 2 = 0 or v + 4 = 0 or v - 4 = 0

Solve

v - 2 = 0 : v = 2

Solve

v + 4 = 0 : v = - 4

Solve

v - 4 = 0 : v = 4

The solutions are

v = 2, v = - 4, v = 4

r^{4} - 2 r^{3} + 10 r^{2} - 18 r + 9 = 0

0 = x^{3} + 2 x^{2} - 4 x - 8

x, y + 3 = x^{3}

x, y^{4} = - x^{4}

x^{3} - 5 x^{2} - 50 x = 0

What are the solutions to the equation v^3-2v^2-16v=-32 ?
The solutions to the equation v^3-2v^2-16v=-32 are v=2,v=-4,v=4
Find the zeros of v^3-2v^2-16v=-32
The zeros of v^3-2v^2-16v=-32 are v=2,v=-4,v=4