What are the solutions to the equation (1+0.01)^{12}=(1+x)^6 ?

The solutions to the equation (1+0.01)^{12}=(1+x)^6 are x=0.0201,x=-2.0201

Find the zeros of (1+0.01)^{12}=(1+x)^6

The zeros of (1+0.01)^{12}=(1+x)^6 are x=0.0201,x=-2.0201

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(1 + 0.01)^{12} = (1 + x)^{6}

x = 0.0201, x = - 2.0201

Solution steps

(1 + 0.01)^{12} = (1 + x)^{6}

Switch sides

(1 + x)^{6} = (1 + 0.01)^{12}

Simplify

(1 + 0.01)^{12} : 1.12682 \dots

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0.0201, x = - 2.0201

x^{4} + x^{2} + x + 1 = 0

4 = x^{4}

4 = x^{3}

x^{8} - 29 x^{4} + 100 = 0

4 x^{3} - 15 x^{2} = 0

What are the solutions to the equation (1+0.01)^{12}=(1+x)^6 ?
The solutions to the equation (1+0.01)^{12}=(1+x)^6 are x=0.0201,x=-2.0201
Find the zeros of (1+0.01)^{12}=(1+x)^6
The zeros of (1+0.01)^{12}=(1+x)^6 are x=0.0201,x=-2.0201