What are the solutions to the equation (x+4)(x+2)(x-1)(x-3)=0 ?

The solutions to the equation (x+4)(x+2)(x-1)(x-3)=0 are x=-4,x=-2,x=1,x=3

Find the zeros of (x+4)(x+2)(x-1)(x-3)=0

The zeros of (x+4)(x+2)(x-1)(x-3)=0 are x=-4,x=-2,x=1,x=3

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(x + 4) (x + 2) (x - 1) (x - 3) = 0

x = - 4, x = - 2, x = 1, x = 3

Solution steps

(x + 4) (x + 2) (x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 2 = 0 or x - 1 = 0 or x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 2 = 0 : x = - 2

Solve

x - 1 = 0 : x = 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 4, x = - 2, x = 1, x = 3

2 x^{3} + 7 x^{2} + 4 x - 4 = 0

x (x - 1)^{2} = - (x - 1) (3 x + 2)

x^{4} - 2 x^{3} + 6 x^{2} - 2 x + 5 = 0

x^{3} - 10 x = 0

x^{3} - 6 x^{2} + 9 x - 2 = 0

What are the solutions to the equation (x+4)(x+2)(x-1)(x-3)=0 ?
The solutions to the equation (x+4)(x+2)(x-1)(x-3)=0 are x=-4,x=-2,x=1,x=3
Find the zeros of (x+4)(x+2)(x-1)(x-3)=0
The zeros of (x+4)(x+2)(x-1)(x-3)=0 are x=-4,x=-2,x=1,x=3