What are the solutions to the equation x^3+4x^2+6x=0 ?

The solutions to the equation x^3+4x^2+6x=0 are x=0,x=-2+sqrt(2)i,x=-2-sqrt(2)i

Find the zeros of x^3+4x^2+6x=0

The zeros of x^3+4x^2+6x=0 are x=0,x=-2+sqrt(2)i,x=-2-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + 4 x^{2} + 6 x = 0

x = 0, x = - 2 + 2 i, x = - 2 - 2 i

Solution steps

x^{3} + 4 x^{2} + 6 x = 0

Factor

x^{3} + 4 x^{2} + 6 x : x (x^{2} + 4 x + 6)

x (x^{2} + 4 x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 x + 6 = 0

Solve

x^{2} + 4 x + 6 = 0 : x = - 2 + 2 i, x = - 2 - 2 i

The solutions are

x = 0, x = - 2 + 2 i, x = - 2 - 2 i

(x^{2} + 2 x) (x^{2} + 2 x - 7) = 8

- x^{4} + 7 x^{3} - 6 x^{2} = 0

x^{4} + 5 x^{2} - 14 = 0

x, x^{3} - y = 2

x, x^{3} - y = 1

What are the solutions to the equation x^3+4x^2+6x=0 ?
The solutions to the equation x^3+4x^2+6x=0 are x=0,x=-2+sqrt(2)i,x=-2-sqrt(2)i
Find the zeros of x^3+4x^2+6x=0
The zeros of x^3+4x^2+6x=0 are x=0,x=-2+sqrt(2)i,x=-2-sqrt(2)i