What are the solutions to the equation 2x(4x^4)=(2x^5)x^4 ?

The solutions to the equation 2x(4x^4)=(2x^5)x^4 are x=0,x=sqrt(2)i,x=-sqrt(2)i,x=-sqrt(2),x=sqrt(2)

Find the zeros of 2x(4x^4)=(2x^5)x^4

The zeros of 2x(4x^4)=(2x^5)x^4 are x=0,x=sqrt(2)i,x=-sqrt(2)i,x=-sqrt(2),x=sqrt(2)

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2 x (4 x^{4}) = (2 x^{5}) x^{4}

x = 0, x = 2 i, x = - 2 i, x = - 2, x = 2

Solution steps

2 x (4 x^{4}) = (2 x^{5}) x^{4}

Move

(2 x^{5}) x^{4}

to the left side

2 x \cdot 4 x^{4} - 2 x^{5} x^{4} = 0

Factor

2 x \cdot 4 x^{4} - 2 x^{5} x^{4} : - 2 x^{5} (x^{2} + 2) (x + 2) (x - 2)

- 2 x^{5} (x^{2} + 2) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 2 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2 i, x = - 2 i, x = - 2, x = 2

x^{3} - 16 x^{2} + 60 x = 0

z^{4} + 35 z^{2} - 36 = 0

x^{3} + 2 x^{2} - 4 x + 2 = 0

4 x^{4} + 3 x^{3} = 0

(x^{2} + 2) (x + 5) = 0

What are the solutions to the equation 2x(4x^4)=(2x^5)x^4 ?
The solutions to the equation 2x(4x^4)=(2x^5)x^4 are x=0,x=sqrt(2)i,x=-sqrt(2)i,x=-sqrt(2),x=sqrt(2)
Find the zeros of 2x(4x^4)=(2x^5)x^4
The zeros of 2x(4x^4)=(2x^5)x^4 are x=0,x=sqrt(2)i,x=-sqrt(2)i,x=-sqrt(2),x=sqrt(2)