What are the solutions to the equation x^3-7x+4=0 ?

The solutions to the equation x^3-7x+4=0 are x\approx 0.60270…,x\approx 2.29240…,x\approx-2.89510…

Find the zeros of x^3-7x+4=0

The zeros of x^3-7x+4=0 are x\approx 0.60270…,x\approx 2.29240…,x\approx-2.89510…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 7 x + 4 = 0

x \approx 0.60270 \dots, x \approx 2.29240 \dots, x \approx - 2.89510 \dots

Solution steps

x^{3} - 7 x + 4 = 0

Find one solution for

x^{3} - 7 x + 4 = 0

using Newton-Raphson:

x \approx 0.60270 \dots

Apply long division:

\frac{x ^{3} - 7 x + 4}{x - 0.60270 \dots} = x^{2} + 0.60270 \dots x - 6.63674 \dots

x^{2} + 0.60270 \dots x - 6.63674 \dots \approx 0

Find one solution for

x^{2} + 0.60270 \dots x - 6.63674 \dots = 0

using Newton-Raphson:

x \approx 2.29240 \dots

Apply long division:

\frac{x ^{2} + 0.60270 \dots x - 6.63674 \dots}{x - 2.29240 \dots} = x + 2.89510 \dots

x + 2.89510 \dots \approx 0

x \approx - 2.89510 \dots

The solutions are

x \approx 0.60270 \dots, x \approx 2.29240 \dots, x \approx - 2.89510 \dots

y, x = y^{3} - 6

x^{3} - 6 x^{2} + 13 x - 12 = 0

x^{2} - 5 x = 2 x^{3} - 4 x^{2} - x + 6

1200 = 600 x^{2} (3 - x)

x^{4} - 3 x^{2} = 10

What are the solutions to the equation x^3-7x+4=0 ?
The solutions to the equation x^3-7x+4=0 are x\approx 0.60270…,x\approx 2.29240…,x\approx-2.89510…
Find the zeros of x^3-7x+4=0
The zeros of x^3-7x+4=0 are x\approx 0.60270…,x\approx 2.29240…,x\approx-2.89510…