What are the solutions to the equation x^3-2x^2-4x+3=0 ?

The solutions to the equation x^3-2x^2-4x+3=0 are x=3,x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

Find the zeros of x^3-2x^2-4x+3=0

The zeros of x^3-2x^2-4x+3=0 are x=3,x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

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x^{3} - 2 x^{2} - 4 x + 3 = 0

x = 3, x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

Decimal Notation

x = 3, x = 0.61803 \dots, x = - 1.61803 \dots

Solution steps

x^{3} - 2 x^{2} - 4 x + 3 = 0

Factor

x^{3} - 2 x^{2} - 4 x + 3 : (x - 3) (x^{2} + x - 1)

(x - 3) (x^{2} + x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + x - 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + x - 1 = 0 : x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

The solutions are

x = 3, x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

x^{3} + x^{2} + 16 x + 16 = 0

x^{4} + 2 x^{3} - 13 x^{2} - 14 x + 24 = 0

x, x^{4} - 1 = 0

z^{4} = 1 - i

5 x^{3} + x = 0

What are the solutions to the equation x^3-2x^2-4x+3=0 ?
The solutions to the equation x^3-2x^2-4x+3=0 are x=3,x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2
Find the zeros of x^3-2x^2-4x+3=0
The zeros of x^3-2x^2-4x+3=0 are x=3,x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2