What are the solutions to the equation x^3-x^2-4x=-4 ?

The solutions to the equation x^3-x^2-4x=-4 are x=1,x=-2,x=2

Find the zeros of x^3-x^2-4x=-4

The zeros of x^3-x^2-4x=-4 are x=1,x=-2,x=2

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x^{3} - x^{2} - 4 x = - 4

x = 1, x = - 2, x = 2

Solution steps

x^{3} - x^{2} - 4 x = - 4

Move

4

to the left side

x^{3} - x^{2} - 4 x + 4 = 0

Factor

x^{3} - x^{2} - 4 x + 4 : (x - 1) (x + 2) (x - 2)

(x - 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = - 2, x = 2

x^{4} + 2 x^{2} = 24

y^{3} + y = 2

x, (3 x y - x)^{3} = 6 y^{2}

x^{3} - x^{2} = 400

7 x^{6} + 35 x^{4} + 4 = 0

What are the solutions to the equation x^3-x^2-4x=-4 ?
The solutions to the equation x^3-x^2-4x=-4 are x=1,x=-2,x=2
Find the zeros of x^3-x^2-4x=-4
The zeros of x^3-x^2-4x=-4 are x=1,x=-2,x=2