What are the solutions to the equation 25x^4-34x^2+9=0 ?

The solutions to the equation 25x^4-34x^2+9=0 are x=1,x=-1,x= 3/5 ,x=-3/5

Find the zeros of 25x^4-34x^2+9=0

The zeros of 25x^4-34x^2+9=0 are x=1,x=-1,x= 3/5 ,x=-3/5

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25 x^{4} - 34 x^{2} + 9 = 0

x = 1, x = - 1, x = \frac{3}{5}, x = - \frac{3}{5}

Decimal Notation

x = 1, x = - 1, x = 0.6, x = - 0.6

Solution steps

25 x^{4} - 34 x^{2} + 9 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

25 u^{2} - 34 u + 9 = 0

Solve

25 u^{2} - 34 u + 9 = 0 : u = 1, u = \frac{9}{25}

u = 1, u = \frac{9}{25}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = \frac{9}{25} : x = \frac{3}{5}, x = - \frac{3}{5}

The solutions are

x = 1, x = - 1, x = \frac{3}{5}, x = - \frac{3}{5}

x^{4} - 8 x^{3} + 17 x^{2} - 8 x + 1 = 0

5 x^{4} = 45 x^{2}

x^{3} + 3 x^{2} - x - 2 = 0

3 x^{3} + 16 = x^{2} + 48 x

(5 x - 3)^{2} (2 x + 3)^{3} = 100

What are the solutions to the equation 25x^4-34x^2+9=0 ?
The solutions to the equation 25x^4-34x^2+9=0 are x=1,x=-1,x= 3/5 ,x=-3/5
Find the zeros of 25x^4-34x^2+9=0
The zeros of 25x^4-34x^2+9=0 are x=1,x=-1,x= 3/5 ,x=-3/5