What are the solutions to the equation 3x^4+24x=0 ?

The solutions to the equation 3x^4+24x=0 are x=0,x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

Find the zeros of 3x^4+24x=0

The zeros of 3x^4+24x=0 are x=0,x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i

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3 x^{4} + 24 x = 0

x = 0, x = - 2, x = 1 - 3 i, x = 1 + 3 i

Solution steps

3 x^{4} + 24 x = 0

Factor

3 x^{4} + 24 x : 3 x (x^{3} + 8)

3 x (x^{3} + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{3} + 8 = 0

Solve

x^{3} + 8 = 0 : x = - 2, x = 1 - 3 i, x = 1 + 3 i

The solutions are

x = 0, x = - 2, x = 1 - 3 i, x = 1 + 3 i

x, e^{t} = x^{6}

4 x^{3} - 36 x^{2} - 96 x - 64 = 0

8 x^{3} - 8 = 0

x^{4} \cdot 5^{4} = (- 1 0^{4})

x, x^{3} - y^{4} = 3

What are the solutions to the equation 3x^4+24x=0 ?
The solutions to the equation 3x^4+24x=0 are x=0,x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i
Find the zeros of 3x^4+24x=0
The zeros of 3x^4+24x=0 are x=0,x=-2,x=1-sqrt(3)i,x=1+sqrt(3)i