What are the solutions to the equation 20x+8x^2-x^3=0 ?

The solutions to the equation 20x+8x^2-x^3=0 are x=0,x=-2,x=10

Find the zeros of 20x+8x^2-x^3=0

The zeros of 20x+8x^2-x^3=0 are x=0,x=-2,x=10

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20 x + 8 x^{2} - x^{3} = 0

x = 0, x = - 2, x = 10

Solution steps

20 x + 8 x^{2} - x^{3} = 0

Factor

20 x + 8 x^{2} - x^{3} : - x (x + 2) (x - 10)

- x (x + 2) (x - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 10 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 10 = 0 : x = 10

The solutions are

x = 0, x = - 2, x = 10

- 10 x - (9 x + 6) = 3 + x^{3} + x

x^{4} = 20736

x^{3} + x^{2} - 36 x - 36 = 0

x^{3} - 11 x^{2} + 38 x - 44 = 0

x, y^{2} = 2 x^{4} + 6

What are the solutions to the equation 20x+8x^2-x^3=0 ?
The solutions to the equation 20x+8x^2-x^3=0 are x=0,x=-2,x=10
Find the zeros of 20x+8x^2-x^3=0
The zeros of 20x+8x^2-x^3=0 are x=0,x=-2,x=10