What are the solutions to the equation 16x^4=81 ?

The solutions to the equation 16x^4=81 are x= 3/2 ,x=-3/2 ,x= 3/2 i,x=-3/2 i

Find the zeros of 16x^4=81

The zeros of 16x^4=81 are x= 3/2 ,x=-3/2 ,x= 3/2 i,x=-3/2 i

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16 x^{4} = 81

x = \frac{3}{2}, x = - \frac{3}{2}, x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

16 x^{4} = 81

Divide both sides by

16

x^{4} = \frac{81}{16}

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = \frac{81}{16}

Solve

u^{2} = \frac{81}{16} : u = \frac{81}{16}, u = - \frac{81}{16}

u = \frac{81}{16}, u = - \frac{81}{16}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{81}{16} : x = \frac{3}{2}, x = - \frac{3}{2}

Solve

x^{2} = - \frac{81}{16} : x = \frac{3}{2} i, x = - \frac{3}{2} i

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}, x = \frac{3}{2} i, x = - \frac{3}{2} i

x^{4} + x^{3} + 7 x^{2} + 9 x - 18 = 0

x^{9} - 1 = 0

2 a^{3} - 3 a^{2} + 1 = 0

x^{5} + x^{3} + x - 3 = 0

x^{3} - x^{2} - 3 x = 0

What are the solutions to the equation 16x^4=81 ?
The solutions to the equation 16x^4=81 are x= 3/2 ,x=-3/2 ,x= 3/2 i,x=-3/2 i
Find the zeros of 16x^4=81
The zeros of 16x^4=81 are x= 3/2 ,x=-3/2 ,x= 3/2 i,x=-3/2 i