What are the solutions to the equation 2x^4-5x^2+36=x^4+8x^2 ?

The solutions to the equation 2x^4-5x^2+36=x^4+8x^2 are x=3,x=-3,x=2,x=-2

Find the zeros of 2x^4-5x^2+36=x^4+8x^2

The zeros of 2x^4-5x^2+36=x^4+8x^2 are x=3,x=-3,x=2,x=-2

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2 x^{4} - 5 x^{2} + 36 = x^{4} + 8 x^{2}

x = 3, x = - 3, x = 2, x = - 2

Solution steps

2 x^{4} - 5 x^{2} + 36 = x^{4} + 8 x^{2}

Move

8 x^{2}

to the left side

2 x^{4} - 13 x^{2} + 36 = x^{4}

Move

x^{4}

to the left side

x^{4} - 13 x^{2} + 36 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 13 u + 36 = 0

Solve

u^{2} - 13 u + 36 = 0 : u = 9, u = 4

u = 9, u = 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 9 : x = 3, x = - 3

Solve

x^{2} = 4 : x = 2, x = - 2

The solutions are

x = 3, x = - 3, x = 2, x = - 2

5 x^{1} + 10 x^{2} + 15 x^{3} = 50

2 x^{4} = 432 x

x^{5} - 80 x + 50 = 0

8 x^{5} - 4 x^{3} + 2 = 0

w^{3} - 2 w^{2} + w - 2 = 0.2

What are the solutions to the equation 2x^4-5x^2+36=x^4+8x^2 ?
The solutions to the equation 2x^4-5x^2+36=x^4+8x^2 are x=3,x=-3,x=2,x=-2
Find the zeros of 2x^4-5x^2+36=x^4+8x^2
The zeros of 2x^4-5x^2+36=x^4+8x^2 are x=3,x=-3,x=2,x=-2