What are the solutions to the equation 4x^2-1=48 ?

The solutions to the equation 4x^2-1=48 are x= 7/2 ,x=-7/2

Find the zeros of 4x^2-1=48

The zeros of 4x^2-1=48 are x= 7/2 ,x=-7/2

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4 x^{2} - 1 = 48

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 3.5, x = - 3.5

Solution steps

4 x^{2} - 1 = 48

Move

1

to the right side

4 x^{2} = 49

Divide both sides by

4

x^{2} = \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{4}, x = - \frac{49}{4}

\frac{49}{4} = \frac{7}{2}

- \frac{49}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

(\frac{12}{5})^{2}

2 x^{2} + x - 10 x - 5

lo g_{81} (\frac{1}{3})

- 11 \leq 3 x + 4 \leq 22

\frac{5}{x} - \frac{3}{y}

What are the solutions to the equation 4x^2-1=48 ?
The solutions to the equation 4x^2-1=48 are x= 7/2 ,x=-7/2
Find the zeros of 4x^2-1=48
The zeros of 4x^2-1=48 are x= 7/2 ,x=-7/2