What are the solutions to the equation y^3+5y^2-49y-245=0 ?

The solutions to the equation y^3+5y^2-49y-245=0 are y=-5,y=-7,y=7

Find the zeros of y^3+5y^2-49y-245=0

The zeros of y^3+5y^2-49y-245=0 are y=-5,y=-7,y=7

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y^{3} + 5 y^{2} - 49 y - 245 = 0

y = - 5, y = - 7, y = 7

Solution steps

y^{3} + 5 y^{2} - 49 y - 245 = 0

Factor

y^{3} + 5 y^{2} - 49 y - 245 : (y + 5) (y + 7) (y - 7)

(y + 5) (y + 7) (y - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 5 = 0 or y + 7 = 0 or y - 7 = 0

Solve

y + 5 = 0 : y = - 5

Solve

y + 7 = 0 : y = - 7

Solve

y - 7 = 0 : y = 7

The solutions are

y = - 5, y = - 7, y = 7

x^{3} + 6 x^{2} - 9 x + 4 = 0

y, y^{3} = x^{3} - 9 x

x^{3} - 2 x^{2} - x = 0

x^{4} - 4 x^{2} + 5 = 0 - 1

(x^{3} - 2) = - 25

What are the solutions to the equation y^3+5y^2-49y-245=0 ?
The solutions to the equation y^3+5y^2-49y-245=0 are y=-5,y=-7,y=7
Find the zeros of y^3+5y^2-49y-245=0
The zeros of y^3+5y^2-49y-245=0 are y=-5,y=-7,y=7